All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
7151
The ratio of the ages of Tina and Rakesh is 9 : 10. Ten years ago, the ratio of their ages was 4 : 5. What is the present age of Rakesh?
Answer:
20 years
Ages 9x, 10x. (9x - 10) / (10x - 10) = 4 / 5 => 45x - 50 = 40x - 40 => 5x = 10 => x = 2. Rakesh = 10x = 20 years.
7152
If 6 years are subtracted from the present age of Gagan and the remainder is divided by 18, then the present age of his grandson Anup is obtained. If Anup is 2 years younger to Mahesh whose age is 5 years, then what is Gagan's present age?
Answer:
60 years
Mahesh = 5. Anup = 5 - 2 = 3. (Gagan - 6) / 18 = Anup = 3 => Gagan - 6 = 54 => Gagan = 60 years.
7153
The sum of the ages of a mother and her daughter is 50. Twelve years ago, the mother was 12 times as old as her daughter. What is the daughter's present age?
Answer:
14
M + D = 50. M - 12 = 12(D - 12) => (50 - D) - 12 = 12D - 144 => 38 - D = 12D - 144 => 13D = 182 => D = 14 years.
7154
The ratio of the ages of Swati and Varun is 2 : 5. After 8 years, their ages will be in the ratio 1 : 2. What is the difference in their present ages?
Answer:
24
Ages: 2x, 5x. (2x + 8) / (5x + 8) = 1 / 2 => 4x + 16 = 5x + 8 => x = 8. Difference = 5x - 2x = 3x = 24 years.
7155
Raju's age after 15 years will be 5 times his age 5 years back. What is the present age of Raju?
Answer:
10 years
Let present age be R. R + 15 = 5(R - 5) => R + 15 = 5R - 25 => 4R = 40 => R = 10 years.
7156
Kamal is 4 times as old as his son. In 10 years, he will be twice as old as his son. What is Kamal's present age?
Answer:
20
K = 4S. K + 10 = 2(S + 10) => 4S + 10 = 2S + 20 => 2S = 10 => S = 5. K = 4(5) = 20 years.
7157
The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
Answer:
33 years
F = 3S + 3. After 3 years: F + 3 = 2(S + 3) + 10. Substitute F: (3S + 3) + 3 = 2S + 6 + 10 => 3S + 6 = 2S + 16 => S = 10. F = 3(10) + 3 = 33 years.
7158
The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be double the sum of the ages of his sons. The father's present age is:
Answer:
45
Let sum of sons' ages be S. Father F = 3S. After 5 years, F + 5 = 2(S + 10) (since there are 2 sons, sum increases by 10). 3S + 5 = 2S + 20 => S = 15. Father = 3 * 15 = 45 years.
7159
The ratio of the ages of a father and son is 5 : 2. If the product of their ages is 1000, then what is the age of the father after 10 years?
Answer:
60
Let ages be 5x and 2x. Product = 10x^2 = 1000 => x^2 = 100 => x = 10. Father's present age = 50. After 10 years = 50 + 10 = 60.
7160
10 years ago, A was half of B's age. If their present ages are in the ratio 3 : 4, find the sum of their present ages.
Answer:
35
Present ages = 3x, 4x. 10 years ago: 3x - 10 = (1/2)(4x - 10) => 6x - 20 = 4x - 10 => 2x = 10 => x = 5. Present ages are 15 and 20. Sum = 35.