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Calendar set-1
Calendar
· Mathematics/General Ability
212 MCQs
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of 212 MCQs
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1
How many days are there in a standard leap year?
Answer:
366
A standard leap year has one extra day added to the month of February, making it 29 days long instead of 28. Therefore, a leap year has 366 days in total.
2
How many odd days are there in an ordinary year?
Answer:
1
An ordinary year has 365 days. When we divide 365 by 7 to find the number of weeks, we get 52 weeks and 1 remainder day. This 1 remaining day is known as the odd day.
3
How many odd days are there in a leap year?
Answer:
2
A leap year has 366 days. Dividing 366 by 7 gives 52 weeks with a remainder of 2 days. These 2 remainder days are the odd days in a leap year.
4
Which of the following is a leap year?
Answer:
1996
A year is a leap year if it is divisible by 4. However, century years (ending in 00) must be divisible by 400 to be leap years. 1900, 2100, and 2200 are not divisible by 400, so they are not leap years. 1998 is not divisible by 4. Wait, 1998 is not a leap year (1998/4 = 499.5). Let's provide a correct option. 1996 is a leap year.
5
Which of the following is not a leap year?
Answer:
1800
For century years (years ending with 00) to be leap years, they must be perfectly divisible by 400. While 1200, 1600, and 2000 are all divisible by 400, 1800 is not. Thus, 1800 is not a leap year.
6
How many odd days are there in 100 years?
Answer:
5
100 years contain 24 leap years and 76 ordinary years. Total odd days = (24 × 2) + (76 × 1) = 48 + 76 = 124 days. Dividing 124 by 7 gives 17 weeks and a remainder of 5. So, there are 5 odd days in 100 years.
7
How many odd days are there in 200 years?
Answer:
3
Since 100 years have 5 odd days, 200 years will have 5 × 2 = 10 odd days. Dividing 10 by 7 leaves a remainder of 3. Therefore, 200 years contain 3 odd days.
8
How many odd days are there in 300 years?
Answer:
1
100 years have 5 odd days. Thus, 300 years will have 5 × 3 = 15 odd days. Dividing 15 by 7 gives 2 weeks with a remainder of 1 day. So, 300 years contain 1 odd day.
9
What was the day of the week on 15th August 1947?
Answer:
Friday
1946 years = 1600 (0 odd days) + 300 (1 odd day) + 46 (11 leap + 35 ordinary = 57 odd days = 1 odd day). Total odd days till 1946 = 2. Odd days from Jan 1 to Aug 15, 1947 = 227 days = 3 odd days. Total = 2 + 3 = 5 odd days. Day 5 is Friday.
10
What was the day of the week on 26th January 1950?
Answer:
Thursday
1949 years = 1600 + 300 + 49. Odd days = 0 + 1 + (12 × 2 + 37 × 1) = 1 + 61 = 62 = 6 odd days. Days in 1950 up to Jan 26 = 26 = 5 odd days. Total odd days = 6 + 5 = 11. 11 mod 7 = 4 odd days. Day 4 is Thursday.
11
If today is Monday, what day of the week will it be after 61 days?
Answer:
Saturday
Every 7 days, the day of the week repeats. Dividing 61 by 7 gives a remainder of 5 (since 56 is exactly divisible by 7). Counting 5 days forward from Monday brings us to Saturday.
12
The calendar for the year 2005 is the same as for the year:
Answer:
2011
2005 is a year immediately following a leap year (2004). The calendar for a year that comes right after a leap year repeats after 6 years. Therefore, 2005 + 6 = 2011.
13
The calendar for the year 2007 will be the same for the year:
Answer:
2018
2007 is three years after the leap year 2004. Calendars for years that are 2 or 3 years after a leap year repeat after 11 years. Therefore, 2007 + 11 = 2018.
14
The calendar for the year 2012 will be the same for the year:
Answer:
2040
2012 is a leap year. The calendar of a leap year repeats exactly after 28 years. Therefore, the calendar for 2012 will be identical to the calendar for 2012 + 28 = 2040.
15
January 1, 2006 was Sunday. What was the day of the week on January 1, 2010?
Answer:
Friday
The years 2006, 2007, and 2009 are ordinary years (1 odd day each), and 2008 is a leap year (2 odd days). Total odd days between Jan 1, 2006, and Jan 1, 2010 = 1 + 1 + 2 + 1 = 5. Adding 5 days to Sunday gives Friday.
16
On what dates of April 2001 did Wednesday fall?
Answer:
4th, 11th, 18th, 25th
First, find the day on 1st April 2001. 2000 years have 0 odd days. Days in 2001 up to April 1 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1 (Apr) = 91 days. 91 mod 7 = 0 odd days. 0 means Sunday. So, 1st April was Sunday. Consequently, the first Wednesday is on the 4th, and then 11th, 18th, 25th.
17
The last day of a century cannot be:
Answer:
Tuesday
The number of odd days in 100, 200, 300, and 400 years are 5, 3, 1, and 0 respectively. These correspond to Friday, Wednesday, Monday, and Sunday. Therefore, the last day of a century cannot be Tuesday, Thursday, or Saturday.
18
The first day of a century cannot be:
Answer:
Sunday
The last day of centuries can only be Sunday, Monday, Wednesday, or Friday. Therefore, the first day of the next century must be the day after these: Monday, Tuesday, Thursday, or Saturday. Thus, the first day cannot be Sunday, Wednesday, or Friday.
19
If 8th of a month falls 3 days after Sunday, what day will be the 17th of that month?
Answer:
Friday
Three days after Sunday is Wednesday. So, the 8th of the month is Wednesday. The 15th will also be a Wednesday (since 8 + 7 = 15). Adding 2 days to the 15th brings us to the 17th, which will be Friday.
20
Today is Thursday. What will be the day of the week after 132 days?
Answer:
Wednesday
To find the day, calculate the remainder of 132 divided by 7. 132 / 7 = 18 with a remainder of 6. This means 132 days contain 18 full weeks and 6 odd days. Thursday + 6 days = Wednesday.
