All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
7061
The age of a father is the sum of the ages of his 3 children. 10 years hence, the father's age will be equal to the sum of the ages of the 2 eldest children. If the youngest child is 10 years old, what is the father's present age?
Answer:
Data inadequate
F = C1 + C2 + 10. F + 10 = (C1 + 10) + (C2 + 10) => F + 10 = C1 + C2 + 20 => F = C1 + C2 + 10. This perfectly aligns with the first statement, providing no unique solution.
7062
A is 10 years older than B. If 5 years ago, A was twice as old as B, what is the present age of B?
Answer:
15
A = B + 10. A - 5 = 2(B - 5). Substitute A: B + 5 = 2B - 10 => B = 15.
7063
The ages of A and B are in the ratio 1:2. The ages of B and C are in the ratio 3:4. If C is 40 years old, what is the age of A?
Answer:
15
C = 40. B = (3/4) * 40 = 30. A = (1/2) * 30 = 15.
7064
The average age of 4 brothers is 15. If the age of the youngest is 6, what is the average age of the remaining 3 brothers?
Answer:
18
Sum of 4 = 60. Sum of 3 = 60 - 6 = 54. Average of 3 = 54 / 3 = 18.
7065
Five years ago, the ratio of A's age to B's age was 3:4. The present sum of their ages is 45. What is the present age of A?
Answer:
20
Sum 5 years ago = 45 - 10 = 35. Ratio 3:4. Total parts 7. 1 part = 5. A's age 5 years ago = 15. Present age = 20.
7066
The ratio of the ages of A and B is 2:3. The ratio of B to C is 4:5. If the sum of their ages is 105, find the age of B.
Answer:
36
A:B = 8:12, B:C = 12:15. A:B:C = 8:12:15. Sum of parts = 35. 35 parts = 105 => 1 part = 3. B = 12 * 3 = 36.
7067
A father is 4 times as old as his son. In 20 years, he will be twice as old as his son. Find the present age of the son.
Answer:
10
F = 4S. F + 20 = 2(S + 20) => 4S + 20 = 2S + 40 => 2S = 20 => S = 10.
7068
A is twice as old as B, who is twice as old as C. If the sum of their ages is 42, find the age of A.
Answer:
24
C = x, B = 2x, A = 4x. Sum = 7x = 42 => x = 6. A = 4(6) = 24.
7069
The sum of the ages of A and B is 48. If A is 3 times as old as B, find the difference in their ages.
Answer:
24
A + B = 48, A = 3B => 4B = 48 => B = 12. A = 36. Difference = 36 - 12 = 24.
7070
The difference between the ages of a father and son is 30. In 10 years, the ratio of their ages will be 3:1. What is the father's present age?
Answer:
35
Difference is always 30. In 10 years, ratio 3:1 means difference is 2 parts. 2 parts = 30 => 1 part = 15. Father in 10 years = 3 * 15 = 45. Present age = 35.