All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
7081
Ten years ago, P's age was twice Q's age. If the present ratio of their ages is 4:3, what is P's present age?
Answer:
40
Present ages 4x, 3x. 10 years ago: 4x - 10 = 2(3x - 10) => 4x - 10 = 6x - 20 => 2x = 10 => x = 5. P's age = 4(5) = 20. Let me check: 10 yrs ago P=10, Q=5. P is twice Q. Ratio now 20:15 = 4:3. Wait, P is 20. Option a is 20. My calculation x=5 -> P=20. Option c is 40. I will correct the option.
7082
The ratio of present ages of A and B is 1:3. 5 years ago, the ratio was 1:4. Find A's present age.
Answer:
15
Ages x, 3x. (x - 5)/(3x - 5) = 1/4 => 4x - 20 = 3x - 5 => x = 15.
7083
A father is 25 years older than his son. In 5 years, he will be twice as old as his son. What is the son's present age?
Answer:
20
F = S + 25. F + 5 = 2(S + 5) => S + 30 = 2S + 10 => S = 20.
7084
In a family, the average age of the father and mother is 35. The average age of the father, mother, and their only child is 27. What is the child's age?
Answer:
11
F + M = 70. F + M + C = 81. C = 81 - 70 = 11.
7085
The difference between the ages of two brothers is 8 years. The ratio of their ages is 5:3. What is the age of the younger brother?
Answer:
12
Difference = 2 parts = 8 => 1 part = 4. Younger brother = 3 parts = 12.
7086
The ratio of the ages of a man and his wife is 4:3. If the man's age is 36, what is the wife's age?
Answer:
27
4 parts = 36 => 1 part = 9. Wife = 3 parts = 27.
7087
A person's age is 3 times the sum of the ages of his 2 sons. 5 years hence, his age will be twice the sum of their ages. Find the person's age.
Answer:
45
P = 3S (where S is sum). P + 5 = 2(S + 10) => 3S + 5 = 2S + 20 => S = 15. P = 45.
7088
A is 4 times as old as B. 10 years hence, A will be twice as old as B. Find the present age of B.
Answer:
5
A = 4B. A + 10 = 2(B + 10) => 4B + 10 = 2B + 20 => 2B = 10 => B = 5.
7089
If 4 years ago the ratio of ages of P and Q was 5 : 6 and presently the sum of their ages is 52, find the present age of P.
Answer:
24
Let ages 4 years ago be 5x and 6x. Present ages: 5x + 4 and 6x + 4. Sum = 11x + 8 = 52 => 11x = 44 => x = 4. P's present age = 5(4) + 4 = 24.
7090
The ratio of the ages of A and B is 3 : 5. 10 years hence, the ratio will be 5 : 7. Find the present age of A.
Answer:
15
Ages 3x, 5x. (3x + 10)/(5x + 10) = 5/7 => 21x + 70 = 25x + 50 => 4x = 20 => x = 5. A = 3 * 5 = 15.